Question

You observe that in a population of humans that the ADH locus has the following genotype...

You observe that in a population of humans that the ADH locus has the following genotype counts: AA = 300, Aa = 500, and aa = 200. What are the expected Hardy-Weinberg genotype frequencies for this locus in this population?

A. 0.3025 (AA), 0.495 (Aa), 0.2025 (aa)

B. 0.2500 (AA), 0.500 (Aa), 0.2500 (aa)

C. 0.5500 (A), 0.4500 (a)

D. 1.000 (AA), 0.000 (Aa), 0.000 (aa)

E. 0.333 (AA), 0.333 (Aa), 0.334 (aa)

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Answer #1

Answer:Hardy Weinberg genotype fequency in a population is defined as the number of individuals of a given genotype divided by the total number of individuals in the population

Genotype counts of AA= 300

Genotype count of Aa = 500

Genotype count of aa = 200

Total count = 300 + 500 + 200 = 1000

Hardy weinberg genotype frequency of AA = 300/1000 = 0.3

Hardy weinberg genotype frequency of Aa = 500/1000 = 0.5

Hardy weinberg genotype frequency of aa = 200/1000 = 0.2

Since these values are closest to these values is in option A

The correct option is A. ( 0.3025 (AA), 0.495 (Aa), 0.2025 (aa) )

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