Question

You performed a dihybrid test cross between flies that were heterozygous for both traits and flies that were homozygous recessive for both traits. The results showed some variation from the predicted 1:1:1:1 phenotypic ratio, but the P value was determined to be .25 (insignificant)or good fit. What can you conclude about these two genes that are responsible for the observed traits and why?   (Hint: law of independent assortment is being tested)

Answer 1

As dinhybrid test cross of result show phenotypic ratio is somewhat different from predicted 1:1:1:1 phenotypic ratio but the p value equal to0.25 which is insignificant it explain that variation in phenotypic ratio is either by chance or due to some experimental error but does not significant to prove linkage of these two genes .so these two genes are either present on same chromosome or significantly apart from each other if present on same chromosome and hence result in independent assortment of these genes from each other during gamete formation.Null Hypothesis that states independent assortment of these two genes occur is accept ed.