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If a man and a woman are heterozygous for a gene, and if they have three...

If a man and a woman are heterozygous for a gene, and if they have three children, what is the chance that all three will be homozygous recessive?

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Answer #1

If a man and woman are heterozygous for a gene-

suppose the gene is A. The two alleles of the gene are A (dominant) and a (recessive). So, the genotype of the man and woman is Aa (heterozygous). The chance of occurence of one homozygous recessive from the cross of two heterozygous is 25% or 1/4 (See figure).  

So if they have 3 children the chance of occurence of all three homozygous recessive (aa) will be -¼ × ¼ × ¼ = 1/64

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