A type A woman is the daughter of a type O father and type A mother. If she has children with a type AB man, what is the probability that their first and second children are AB blood type?
Group of answer choices
1/32
1/4
1/16
1/64
there are three alleles at the ABO locus which determine the blood type, IA, IB and i.
IAIA, IAi- A type blood
IBIB, IBi- B type blood
IAIB- AB type blood
ii- O type blood
The woman has A-type blood and her father has O type blood, which means she has inherited i allele from the father, so her genotype is IAi.
Man has AB type blood so his genotype is IAIB.
IAi * IAIB
IA | i | |
IA | IAIA ( A-type blood) | IAi ( A-type blood) |
IB | IAIB ( AB type blood) | IBi ( B type blood) |
probability of getting a child with AB type blood= number of children with AB type blood/total number of progeny=1/4
probability that their first and second children are AB blood type = (probability of getting a child with AB type blood)^2=(1/4)^2=1/16
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