Question

10:

You are studying a population of lizards. They have two toe lengths, Long(L) and short (l); L is dominant over l. You survey the population two times five years apart and get the following data. Is the population in Hardy-Weinberg equilibrium for toe length? Explain.

Year	LL	Ll	ll	Total
2010	196	168	36	400
2015	98	84	18	200

Answer 1

Ans)

Year2010:

Genotype (LL) frequency=p2=196/400=0.49

Genotype (ll) frequency =q2=36/400=0.09

Genotype (Ll) =168/400=2pq=0.42

Allele (L) frequency=p =p2+1/2(2pq)=0.49+0.21=0.7

Allele(l) frequency =q=q2+1/2(2pq)=0.09+0.21=0.3

p+q=0.7+0.3=1

Here Sum of allele is 1which occur in  population which are in   hardy Weinberg equilibrium so Here this population is in hardy weinberg

Year 2015

LL genotype frequency=98/200=0.49

Ll genotype freq=84/200=0.42

ll genotype frequency =18/200=0.09

Allele l freq=q'=0.09+0.21=0.3

Allele L freq=p '=0.49+0.21=0.7

Here, p'=p

q=q'

p'+q'=1

As allele freq does not change after 5 years which means population is in hardy weinberg equilibrium because hardy weinberg law states that frequeof allele remain constant generation after generation in an ideal population.