If the allele frequency of a dominant allele is 0.6, then the genotype frequency of individuals that are homozygous for the recessive trait is:
60%. |
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48%. |
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40%. |
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36%. |
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16%. |
given
allele frequency = 0.6 ( p)
according to hardy weinberg equilibrium
p+q = 1
so q = 0.4
genotype frequency of individuals that are homozygous for the recessive trait is given by q2
p^2+2pq+q^2=1
where p^2 = Frequency of AA (homozygous dominant) individuals
q^2 = Frequency of aa (homozygous recessive) individuals
2pq = Frequency of Aa (heterozygous) individuals.
therefore q2 = 0.4*0.4 = 0.16
that is 16%
e) 16% is correct answer.
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