Question

A person weighing 180 lbs. runs 4.5 miles per hour for 35 minutes at 2% grade. Compute her VO2 max in ml/kg/min; METS; L/min; and kcals expended using the following formula: (10 pts.) Show your work – you may legibly handwrite this response if you would like. Round to 100th.

               VO₂ (ml/kg^-1/min^-1) = 0.2(speed in m/min) + 0.9(speed in m/min)(fraction grade) + 3.5

Answer 1

given,

weight of person = 180 lbs = 180 / 2.2 = 81.8 kg

speed = 4.5 miles/hour = 4..5 / 0.0372 = 120.96 meter/minute

time = 35 minutes

grade % = 2%

[1 meter/minute = 0.0372 mile/hour]

[ 1 kg = 2.2 lbs]

VO2 max = 0.2 x speed + 0.9 x speed x grade + 3.5

= 0.2 x 120.96 + 0.9 x 120.96 x 2 + 3.5

= 24.192 + 217.728 + 3.5

= 245.42 ml/kg/min

MET = [ speed x ( 0.1 + { grade x 1.8} ) + 3.5] / 3.5

= [ 120.96 x ( 0.1 + { 2 x 1.8} ) + 3.5] / 3.5

= [ 120.96 x ( 0.1 + 3.6 ) + 3.5] / 3.5

= [ 120.96 x 3.7 + 3.5 ] / 3.5

= (447.5 + 3.5 ) / 3.5

= 451 /3.5

= 128.85 METs

Kcal/ min = [MET x body mass (kg) x 3.5] / 200

= [ 128.85 x 81.8 x 3.5 ] / 200

= 36889.75 / 200 = 184.44 kcal/min

Absolute VO2 ( L/min) = [relative VO2 x kg / 1000 ]

= 245.42 x 81.8 / 1000

= 20075.35 / 1000

= 20.07 L / min