Question

1. You are studying the behavior of a perfluorocarbon-based O₂ carrier as an emergency treatment for hypoxemia. It has an approximate molecular radius of 2 nm. Consider ultrafiltration through the kidney (glomerular membrane pore radius 4 nm, length 800 nm). Assuming a therapeutic dose in the blood of 22 mM and 2 mM in the filtrate, determine the electrochemical potential across glomerular membrane.

Answer 1

Answer :)

For Perfluorocarbon based O2 carrier, use the following formula to calculate electrochemical potential across the glomerular membrane:

Here R is gas constant = 8.314 J.K−1.mol−1

T is the absolute temperature in Kelvin.

T = 37 + 273 K

T = 310 K

The z is the valence of ions, which is +1 for CₓFy.

F = Faraday’s constant= 96,485 C.mol−1

[X]out = outside of the membrane concentration of the ion

[X]out = 2 mM

[X]in = inside the concentration of the ion.

[X]in = 22 mM

Put all values in the above formula and calculate the potential:

E = 2.3 x ((310 x 8.3) / (1x 96485)) x log2/22

E = 0.06 x (log1 –log 11)

E = 0.06 x (0 – 1.04)

E = – 0.062 V, or

E = – 0.062 x 1000 mV

E = – 62 mV

Therefore, the electrochemical potential will be -62 mV.