Question

Give a schematic presentation of one mole of hexose sugar is completely burnt in a sugar cane plant in cuba, please ignore all the intermediate products and processes

Answer 1

In the night time plants undergo cellular respiration, so one mole of hexose sugar i.e one Glucose ( C6 H12O6) undercgoes the the process of Glycolysis and then Kreb's TCA cycle. 38 ATP molecules can be made per glucose molecule during cellular respiration (2 from glycolysis, 2 from the Krebs cycle, and about 34 from the electron transport system).

One mole means 6.023 * 1023 molecules of glucose, so 38* 6.023 * 1023 of ATP will be released when one mole of glucose or hexose sugar is burnt in any plant, here a sugarcane plant in Cuba. 228.874 * 1023 molecules of ATP will be released,

1 mole of Glucose 2* 6.023* 1023 molecules of ATP during Glycolysis + 34*6.023 * 1023 molecules of ATP during electron transport chain + 2* 6.023 * 1023 molecules of ATP during Kreb's cycle= 228.874 * 1023 molecules of ATP