Let us consider that the father is heterozygous for B blood group and mother is heterozygous foe Rh antigen.
We'll simply make a Punnet's square to obtain the possible combinations in the offsprings of there two parents.
The diagram depicts that there is 50% possibility of the daughter having B blood group and 50% chance of her being Rh negative.This is how the daughter cam have B negative blood group.
Note- i represents the recessive allele and IB is the B allele.
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