Question

1. A normal individual has within their body 14L of Extracellular fluid and 28 L of...

1. A normal individual has within their body 14L of Extracellular fluid and 28 L of Intracellular fluid and of course the normal mOsMolarity is 300. (From this you should be able to get the total body, ECF, and ICF: solute (mOsmoles), volume, and mOsMolarity During a very hot marathon, a runner drank 4.5 Liters of distilled water (not a good idea during a marathon). Because it was so hot, she also produced 3 L of perspiration containing 0.3% of NaCl which is assumed in this example to be non-penet srating.

a. Convert 0.3% NaCl (58.4grams/mole) to mOsM (milliosmolar) – you will need this for Question 1b.

b. Calculate the solute (mOsmoles), volume, and mOsMolarity in the runner after she completed her marathon for Total Body, ICF and ECF

Homework Answers

Answer #1

a)0.3% Nacl means 0.3 g Nacl in 100 ml solution.

So in 1 liter of solution ,3 g Nacl.

Number of millimoles in 3 g Nacl =(3/58.4)*1000= 51.3 mOsm/L

b)

Before the marathon,

ECF=14 L & ICF=28 L

Usually plasma constitutes 25% of the volume of ECF.

So volume of plasma =3.5 L

Number of solutes = 3.5 * 300 =1050 mOsm

After drinking 4.5 L distilled water, volume is plasma =3.5+4.5 =8 L

But number of solutes remain the same.

Then she lost water and solutes in sweat.

Volume of plasma after sweating =8-3=5 L

Number of solutes lost = 51.3 *3=153.9 mOsm

Number of solutes left=1050-154= 896 mOsm

So milliosmolarity = 896 /5 = 179.2 mOsm/L

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