Suppose you made the intestinal sac too small, and at the end of experiment you could collect only 100 microliters of solution instead of 200 microliters for analysis. You perform the DNS reaction with 100 ul of the recovered solution and 100 ul of water (to bring volume up to 200 ul). How that would affect the concentration of glucose you determined from the standard curve?
Half the true concentration
Twice the true concentration
Equal to the true concentration
As the volume taken in the present example is half (100ul) of the actual volume (200ul) required for the reaction. Since 100ul water has been used to make the final volume as 200ul
Therefore, the dilution factor will be= Final volume= 200ul = 2
Initial volume 100ul
Thus, the actual concentration of glucose will be multiplied by the dilution factor of 2.
Hence, based on the above explination, the concentration of glucose we determined from the standard curve will be Twice the true concentration (option 2)
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