A series of mutations in a biosynthetic pathway of Salmonella result in the requirement of supplements to allow growth (+) as shown in the following table.
R | X | M | K |
Minimal Media |
|
---|---|---|---|---|---|
1 | + | + | - | + | - |
2 | + | - | - | + | - |
3 | + | + | + | + | - |
4 | + | - | - | - | - |
Which of the following steps is regulated by the enzyme that is defective in Mutant 2?
a. R → M
b. M → X
c. X → K
d. K → R
e. M → K
f. K → M
g. R → X
h. M → R
c. X → K
From this data, we can conclude that R is the last molecule in the pathway and is required for growth, as all Mutants can grow on media supplemented with R.
Now, since Mutant 2 can grow in the presence of K and R, therefore, K must be converted to R and this enzyme is functional in Mutant 2. Further, since Mutant 1 can grow on media containing R, K and X, therefore, x must be the precursor to K.
So, Mutant 2 is defective in the conversion of X to K.
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