1. The following data indicate the mean oxygen consumption resulting from running at various steady state running speeds. Graph the following data points using a computer graphics program such as EXCEL. (Put the independent variableon the x axis. Make sure that you include a title and that the axes are labeled). Include (attach) the graph.
Velocity (m/min) |
Oxygen Consumption (ml/kg/min) |
224 |
49 |
221 |
49 |
157 |
37 |
245 |
53 |
208 |
46 |
180 |
41 |
207 |
46 |
212 |
47 |
260 |
54 |
262 |
55 |
180 |
41 |
315 |
64 |
236 |
50 |
240 |
52 |
250 |
52 |
Write 1 sentence describing the relationship between these variables.
10. Using the graph you have constructed (#2 above) create a line of best fit and estimate (eyeball) a person’s approximate oxygen consumption at the following steady state speeds: (Note: 1 mph is approx.. 26.8 m/min). Show work on graph.
a) 5.5 mph: _________________________ b) 195 m/min ___________________
c) NOW… Using the same data and graph you have constructed (#9 above) ask EXCEL to display the regression equation and copy it down. y = _______ (x) + _______
Using this equation determine the relative oxygen consumption (ml/kg/min) for a runner who runs three miles in 22 minutes and 30 seconds (i.e., 22.5 minutes)? (Hint: first determine running velocity (m/min) this is x. (Note: 1 mile = 1609 meters). Use equation: oxygen consumption (y) = _______ (x) + _______ ).
Linear Graph of velocity vs oxygen consumption
Oxygen consumption depends on running velocity. If the velocity increases, the person consumes more amount of oxygen.
10. a) 5.5 mph:
1 mph = 26.8 m/min
Velocity 5.5 mph = 5.5 * 26.8 = 147.4 m/min
Based on graph, interpolate 147.4 on x-axis with the corresponding y- axis value
The oxygen consumption value = approximately 35.5 ml/kg/min
B) 195 m/min
Based on graph, interpolate 195 on x-axis with the corresponding y- axis value
The oxygen consumption value = approximately 44 ml/kg/min
Regression equation: y = 0.168x + 10.9
Distance covered in 22.5 minutes is 3 miles (3*1609 meters = 4827 m)
Velocity = Displacement/Time = 4827/22.5 = 214.5 m/min
Substitute this value in Regression equation y = 0.168x + 10.9
y = 0.168*214.5 + 10.9 = 36.03+10.9 = 46.93 ml/kg/min
Oxygen consumption = 46.93 ml/kg/min
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