pH = 6.1 + log [HCO3-]/[H2CO3]
What is the pH if the ratio of bicarbonate to carbonic acid is
25/1?
pH = 6.1 + log [HCO3-]/[H2CO3]
What is the pH if the ratio of bicarbonate to carbonic acid is
20/1.5?
The arbonic acid-bicarbonate buffer is the most important buffer for maintaining acid-base balance in the blood.
Generally the equation for the pH of the buffer is pH=pK+og [HCO3-]/[H2CO3].
under normal conditions the pK=6.1,so the equation becomes
pH = 6.1 + log [HCO3-]/[H2CO3].
so the above questions can be solved from this
Q1. here the ratio of bicarbonate to carbonic acid is 25/1
so on substituting, pH=6.1+log 1.3979
pH=7.497
Q2. the ratio of bicarbonate to carbonic acid is 20/1.5
so on substituting pH=6.1+log 13.333
pH= 7.22
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