Suppose there are two problems, C and P.
C is known to be NP-Complete
Suppose that I want to prove that P is also NP-Complete
Which of the following is the correct method to do this?
Question 3 options:
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Right option is option (2)
As C is already known to be NP-complete and also polynomial time reducible to P, as asserted in option (2), P has to be NP-complete,otherwise if P is not NP-complete, then by reversing the calculations we can reach from P to C, and in that case C also would not be NP-complete, which is a contradiction about C's NP-completeness.
If we go by the first option then we see, a polynomial-time reduced instance C of P may be NP_complete although P need not be so.
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