Given a, b, c ∈ G, solve for x (show all your steps):
1. {(x∗a∗x)∗(x∗a∗x)∗(x∗a∗x)=b∗x and x∗x∗a=(x∗a)^−1}
2. x∗x∗b = x∗a−1∗c
In the group , and .
Now, left hand side is . So . Then .
. Then . Then relation between a,b,c must be . So we are done.
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