Question

Let z(s,t) z(s,t) be a differentiable function of two variable s and t with continuous first...

Let z(s,t) z(s,t) be a differentiable function of two variable s and t with continuous first partial derivatives. Assume further that s=s(x,y), t=t(x,y) are differentiable functions of variables x and y .

(a) find the general chain rule chain rule for (∂z/∂x)y . Your subscripts will be marked.

(b) Let equations

F(x,y,s,t)=y+x^2+cos(t)−sin(s)+1=0,

G(x,y,s,t)=x+y^2−st−2=0,

implicitly define s , and t as functions of x and y .

Compute ∂s/∂x)y ∂t/∂x)y at the point P(x,y,s,t)=(1,−1,π,0).

(c) Let now z(s,t)=s^2+t. By using the above two parts evaluate ∂z/∂x)y at P defined in part (b).

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Let z=f(a,b,c) where a=g(s,t), b=h(l(s+t),t), c=tsin(s). f,g,h,l are all differentiable functions. Compute the partial derivatives of...
Let z=f(a,b,c) where a=g(s,t), b=h(l(s+t),t), c=tsin(s). f,g,h,l are all differentiable functions. Compute the partial derivatives of z with respect to s and the partial of z with respect to t.
Suppose that  f   is a twice differentiable function and that its second partial derivatives are continuous....
Suppose that  f   is a twice differentiable function and that its second partial derivatives are continuous. Let  h(t) = f (x(t), y(t))  where  x = 2e^ t  and  y = 2t. Suppose that  fx(2, 0) = 1,  fy(2, 0) = 3,  fxx(2, 0) = 4,  fyy(2, 0) = 1,  and  fxy(2, 0) = 4. Find   d ^2h/ dt ^2  when t = 0.
Suppose that  f   is a twice differentiable function and that its second partial derivatives are continuous....
Suppose that  f   is a twice differentiable function and that its second partial derivatives are continuous. Let  h(t) = f (x(t), y(t))  where  x = 3e ^t  and  y = 2t. Suppose that  fx(3, 0) = 2,  fy(3, 0) = 1,  fxx(3, 0) = 3,  fyy(3, 0) = 2,  and  fxy(3, 0) = 1. Find   d 2h dt 2  when t = 0.
Use the Chain Rule to find the indicated partial derivatives. u =sqrt( r^2 + s^2) ,...
Use the Chain Rule to find the indicated partial derivatives. u =sqrt( r^2 + s^2) , r = y + x cos(t), s = x + y sin(t) ∂u ∂x , ∂u ∂y , ∂u ∂t when x = 1, y = 4, t = 0
Let w(x,y,z) = x^2+y^2+z^2 where x=sin(8t), y=cos(8t) , z= e^t Calculate dw/dt by first finding dx/dt,...
Let w(x,y,z) = x^2+y^2+z^2 where x=sin(8t), y=cos(8t) , z= e^t Calculate dw/dt by first finding dx/dt, dy/dt, and dz/dt and using the chain rule dx/dt = dy/dt= dz/dt= now using the chain rule calculate dw/dt 0=
1.) Let f ( x , y , z ) = x ^3 + y +...
1.) Let f ( x , y , z ) = x ^3 + y + z + sin ⁡ ( x + z ) + e^( x − y). Determine the line integral of f ( x , y , z ) with respect to arc length over the line segment from (1, 0, 1) to (2, -1, 0) 2.) Letf ( x , y , z ) = x ^3 * y ^2 + y ^3 * z^...
An implicitly defined function of x, y and z is given along with a point P...
An implicitly defined function of x, y and z is given along with a point P that lies on the surface: sin(xy) + cos(yz) = 0, at P = (2, π/12, 4) Use the gradient ∇F to: (a) find the equation of the normal line to the surface at P. (b) find the equation of the plane tangent to the surface at P.
1. f(x, y, z) = 2x-1 − 3xyz2 + 2z/ x4 2. f(s, t) = e-bst...
1. f(x, y, z) = 2x-1 − 3xyz2 + 2z/ x4 2. f(s, t) = e-bst − a ln(s/t) {NOTE: it is -bst2 } Find the first and second order partial derivatives for question 1 and 2. 3. Let z = 4exy − 4/y and  x = 2t3 , y = 8/t Find dz/dt using the chain rule for question 3.
Use the Chain Rule to find ∂z/∂s and ∂z/∂t. (Enter your answer only in terms of...
Use the Chain Rule to find ∂z/∂s and ∂z/∂t. (Enter your answer only in terms of s and t. Please use * for multiplication between all factors.) z = x2y3, x = s cos(t), y = s sin(t)
Use the Chain Rule to find ∂z/∂s and ∂z/∂t. 3. z=x/y, x=se^t, y=1+se^-t 4. z=e^rcos θ,...
Use the Chain Rule to find ∂z/∂s and ∂z/∂t. 3. z=x/y, x=se^t, y=1+se^-t 4. z=e^rcos θ, r=st, θ=√s^2+t^2