Solve the given initial-value problem in which the input function g(x) is discontinuous. [Hint: Solve the problem on two intervals, and then find a solution so that y and y' are continuous at
x = π/2.]
y'' + 4y = g(x), y(0) = 1, y'(0) = 3, where
g(x) =
sin(x), | 0 ≤ x ≤ π/2 | |
0, | x > π/2 |
Find y(x) for each of the intervals.
, | 0 ≤ x ≤ π/2 | |
, | x > π/2 |
I've attached Handwritten solution for the given problem
Get Answers For Free
Most questions answered within 1 hours.