Using the D-operator Method, get complete specific solutions, including the constants of integration, for the following equation:
3 dx/dt = 5x + 7 x(0+) = -2
Let d/dt=T
So equation is
3T(x)=5x+7
Applying the operator again to above equation
3T(T(x))=5T(x)+T(7)
3T^2(x)=5T(x)+0
(3T^2-5T)(x)=0
(3T-5)T(x)=0
So this is the factorisation of the operator
(3T-5)(x)=C
3Tx-5x=C
x'-(5/3)x=C/3
INtegrating factor is exp(5t/3)
Multiplyinbg gives
(x'-5x/3) exp(5t/3)=C exp(5t/3)/3
(x exp(5t/3))'=C exp(5t/3)/3
Integrating gives
x exp(5t/3)=C exp(5t/3)/5+D
x=C/5+D exp(-5t/3)
x(0)=C/5+D=-2
dx/dt(0)=5x(0)+7=5*(-2)+7=-3
dx/dt=-5D exp(-5t/3)/3
dx/dt(0)=-3=-5D/3
D=9/5
C/5+D=-2
C/5=-2-9/5=-19/5
C=-19
x=-19/5+9/5 exp(-5t/3)
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