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64 students divided into 4 groups.. so each group contains 16 students....
Now we focus on two students A and B .. we find the probability that these are in same group.
So , A is in 1st group .. probability is 16/64 ...
Now B is in this group then probability is 15/63 ...
So probability of A andBboth are in 1st group. = (16/64)*(15/63) ...
Now ,like this we have 4 groups to be placeA and B ...
So ...
Probability = 4*(16/64)*(15/63) = 15/63 = 5/21
Answer = 5/21 ....
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