Let the given function is -
For Vertical Asymptotes -
In order to find vertical asymptotes , we equate the denominator of the above function with zero . So, we have
or ,
,
Which is imaginary , which means it does not exist in real .
Therefore , we will have no vertical asymptotes for the given function f(x).
For Horizontal Asymptotes -
In order to find horizontal asymptotes, we must remember the following rules , which say
Here , in our case , clearly , the polynomial in numerator i.e., 4x is of lower degree (of 1 )than the polynomial in denominator , which is of degree 2 ,
Therefore , Horizontal Asymptote of the given function is x - axis , i.e., y = 0 .
Now Tracing the Curve :
Given function is -
symmetry: Since if we replace x by (-x) and y by (-y) in the above equation , the equation remains unchanged , i.e.,
which implies ,
Therefore , the above function is symmetric in the opposite quadrants .
passing through origin : The given curve passes through origin , if it does not contain any constant term .
So , our curve does not contain any constant term , therefore it passes through origin .
asymptotes ; we have already found out the asymptotes of the function , which have , no vertical asymptote and horizontal asymptote as x-axis i.e., y = 0.
table: Now , we will find some points lying the curve in the following table :
x | 0 | 1 | -1 | 2 | -2 |
y | 0 | 4/3 | -4/3 | 4/3 | -4/3 |
Thus , using above information we will graph the function which comes out be , as given below :
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