Question

A company produces steel rods. The lengths of the steel rods are
normally distributed with a mean of 215.6-cm and a standard
deviation of 2.4-cm. For shipment, 15 steel rods are bundled
together.

Find the probability that the average length of a randomly selected
bundle of steel rods is between 215-cm and 216.5-cm.

*P*(215-cm < *M* < 216.5-cm) =

Enter your answer as a number accurate to 4 decimal places. Answers
obtained using exact *z*-scores or *z*-scores rounded
to 3 decimal places are accepted.

Answer #1

Given

mean

Standard deviation

Sample size

Note By using Calculator (or) Excel formula to find the probability

A company produces steel rods. The lengths of the steel rods are
normally distributed with a mean of 179-cm and a standard deviation
of 2.4-cm. For shipment, 12 steel rods are bundled together.
Find the probability that the average length of a randomly selected
bundle of steel rods is less than 177.8-cm.
P(M < 177.8-cm) =
Enter your answer as a number accurate to 4 decimal places. Answers
obtained using exact z-scores or z-scores rounded
to 3 decimal places are...

A company produces steel rods. The lengths of the steel rods are
normally distributed with a mean of 237.4-cm and a standard
deviation of 1.6-cm. For shipment, 6 steel rods are bundled
together.
Find the probability that the average length of a randomly selected
bundle of steel rods is between 237.5-cm and 239.1-cm.
P(237.5-cm < M < 239.1-cm) =
Enter your answer as a number accurate to 4 decimal places. Answers
obtained using exact z-scores or z-scores rounded
to 3...

A company produces steel rods. The lengths of the steel rods are
normally distributed with a mean of 246.7-cm and a standard
deviation of 0.8-cm. For shipment, 23 steel rods are bundled
together.
Find the probability that the average length of a randomly selected
bundle of steel rods is greater than 246.6-cm.
P(M > 246.6-cm) =
Enter your answer as a number accurate to 4 decimal places. Answers
obtained using exact z-scores or z-scores rounded
to 3 decimal places are...

A company produces steel rods. The lengths of the steel rods are
normally distributed with a mean of 122.8-cm and a standard
deviation of 0.6-cm. For shipment, 6 steel rods are bundled
together.
Find the probability that the average length of a randomly selected
bundle of steel rods is less than 122.7-cm.
P(M < 122.7-cm) =
Enter your answer as a number accurate to 4 decimal places. Answers
obtained using exact z-scores or z-scores rounded
to 3 decimal places are...

A company produces steel rods. The lengths of the steel rods are
normally distributed with a mean of 252.7-cm and a standard
deviation of 2.4-cm. For shipment, 9 steel rods are bundled
together.
Find P82, which is the average length
separating the smallest 82% bundles from the largest 18%
bundles.
P82 = -cm
Enter your answer as a number accurate to 2 decimal place. Answers
obtained using exact z-scores or z-scores rounded
to 3 decimal places are accepted.

A company produces steel rods. The lengths of the steel rods are
normally distributed with a mean of 197.5-cm and a standard
deviation of 2-cm. For shipment, 6 steel rods are bundled
together.
Find P11, which is the average length separating the smallest
11% bundles from the largest 89% bundles.
P11 =______________ -cm
Enter your answer as a number accurate to 2 decimal place.
Answers obtained using exact z-scores or z-scores rounded to 3
decimal places are accepted.

A company produces steel rods. The lengths of the steel rods are
normally distributed with a mean of 179.5-cm and a standard
deviation of 0.7-cm. For shipment, 20 steel rods are bundled
together.
Find P95, which is the average length
separating the smallest 95% bundles from the largest 5%
bundles.
P95 = -cm
Enter your answer as a number accurate to 2 decimal place. Answers
obtained using exact z-scores or z-scores rounded
to 3 decimal places are accepted.

A company produces steel rods. The lengths of the steel rods are
normally distributed with a mean of 216.5-cm and a standard
deviation of 2.3-cm. For shipment, 24 steel rods are bundled
together.
Find P15, which is the average length
separating the smallest 15% bundles from the largest 85%
bundles.
P15 = -cm
Enter your answer as a number accurate to 2 decimal place. Answers
obtained using exact z-scores or z-scores rounded
to 3 decimal places are accepted.

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normally distributed with a mean of 263.6 cm and a standard
deviation of 0.5 cm. For shipment, 27 steel rods are bundled
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Find the probability that the average length of a randomly selected
bundle of steel rods is less than 263.6 cm.
P(¯xx¯ < 263.6 cm) =
Enter your answer as a number accurate to 4 decimal places. Answers
should be obtained using zz scores rounded to...

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normally distributed with a mean of 110.9-cm and a standard
deviation of 0.6-cm. For shipment, 7 steel rods are bundled
together.
Find the probability that the average length of a randomly selected
bundle of steel rods is less than 110.9-cm.
P(M < 110.9-cm) = ______________
Enter your answer as a number accurate to 4 decimal places.

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