A model for a ball thrown into the air with air resistance
proportional to the velocity is given by dv dt = −g−cv. Solve for v
and the position of the ball when c = 0.05.Assume that g = 32
ft/sec2.
Please use ordinary differential equation to solve.
The differential equation is:
This can be solved as:
For the position, we do:
where are constants which can be found from initial conditions. Given the values of and , we can write:
Assuming that the ball is thrown from , we get:
Then:
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