Question

Find the general solution to y'' + 2y' +y = e^{-t}
log(t)

Answer #1

(Higher Order DE) Find the general solution of y'''− 2y''− y'+
2y = e^x?

Find the general solution of the equation.
y''-3y'+2y=e^3t

a) Find the general solution of the differential equation
y''-2y'+y=0
b) Use the method of variation of parameters to find the general
solution of the differential equation y''-2y'+y=2e^t/t^3

find the general solution of the differential equation dy/dt -
2y = t^2 * e^2t

Find the general solution of the given differential
equation.
y'' − y' − 2y = −8t + 6t2
y(t) =

Find a general solution to the given equation for t<0
y"(t)-1/ty'(t)+5/t^2y(t)=0

For 2y' = -tan(t)(y^2-1) find general solution (solve for y(t))
and solve initial value problem y(0) = -1/3

4. For each of the following equations find the general
solution.
(a) y" + 2y' + 2y = etsin(t)
(b) y(4) - 4y" + 4y = et -
te2t

Use the method of Undetermined Coefficients to find the general
solution
y'' - y' -2y = e^(2x)

Solve the following second order differential equations:
(a) Find the general solution of y'' − 2y' = sin(3x) using the
method of undetermined coefficients.
(b) Find the general solution of y'' − 2y'− 3y = te^−t using the
method of variation of parameters.

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