Question

Reduce the following equation to first order and solve

Y” + (1+1/Y) (Y’)^{2} = 0

Please show all steps and give solution.

Answer #1

Please show all steps to the first order equation, using
infinity series.
a) solve:
y' - y = 0
b) solve:
(x-3)y' + 2y = 0

In this problem, you will solve the following first order linear
ODE: y' + (1/x)y = (2/x2 )+ 1 with y(1) = 1.
a) Solve the complimentary equation
b) Use the solution to the complimentary equation to find the
general solution
c) Use the initial conditions to find the specific solution

Solve the 2nd Order Differential Equation using METHOD OF
REDUCTION
Please don't skip steps!
(x-1)y"-xy'+y=0 x>1 y1(x)=x

Reduce the order of the following differential equation and
solve
2x2z'''+ xz''−3z' = 2/x3 ,x >
0.

Please show all steps, thanks!!
a) Solve the BVP: y" + 2y' + y = 0, y(0) = 1, y(1) =3
b) Prove the superposition principle: suppose that the functions
y1(x) and y2(x) satisfy the homogenous equation of order two: ay''
+ by' + cy = 0.
Show that the following combinations also satisfy it:
constant multiple m(x) = k*y1(x)
sum s(x) = y1(x) + y2(x)

Solve the 2nd Order
Differential Equation using METHOD OF REDUCTION
Please don't skip
steps!
(x-1)y"-xy'+y=0 x>1
y1(x)=x
My professor is
getting y2(x)=e^x and I don't understand how!

Solve the first-order linear differential equation:
y ′ + sin ( x ) y = sin ( x ) , y ( 0 ) = 2.

solve the following system of differential equations
and find the general solution
(D+3)x+(D-1)y=0 and 2x+(D-3)y=0
please show the steps

Solve the following differential equations
y''-4y'+4y=(x+1)e2x (Use Wronskian)
y''+(y')2+1=0 (non linear second order equation)

Solve the following differential equations
1. cos(t)y' - sin(t)y = t^2
2. y' - 2ty = t
Solve the ODE
3. ty' - y = t^3 e^(3t), for t > 0
Compare the number of solutions of the following three initial
value problems for the previous ODE
4. (i) y(1) = 1 (ii) y(0) = 1 (iii) y(0) = 0
Solve the IVP, and find the interval of validity of the
solution
5. y' + (cot x)y = 5e^(cos x),...

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