Question

A one parameter family (with parameter cc) of solutions to the problem y′=y−y^2 is y=1/(1+ce−x) Find...

A one parameter family (with parameter cc) of solutions to the problem

y′=y−y^2

is y=1/(1+ce−x)

Find c so that y(−2)=−3

Math   Advanced-Math   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1


0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
(a) verfiy that y=tan(x+c) ia a one parameter family of solutions of the differential equation y'=...
(a) verfiy that y=tan(x+c) ia a one parameter family of solutions of the differential equation y'= 1+x^2 (b)since f(x,y)= 1+y^2 and df/dy= 2y are continuous everywhere, the region R can be taken to be the entire xy-plane. Use the family of solutions in part A to find an explicit solution of the first order initial value problem y'= 1+y^2, y(0)=0. Even though x0=0 is in the interval (-2,2) explain why the solution is not defined on its interval (c)determine the...
In this problem, y = c1ex + c2e−x is a two-parameter family of solutions of the...
In this problem, y = c1ex + c2e−x is a two-parameter family of solutions of the second-order DE y'' − y = 0. Find a solution of the second-order IVP consisting of this differential equation and the given initial conditions. y(−1) = 7,    y'(−1) = −7
In this problem, y = c1ex + c2e−x  is a two-parameter family of solutions of the second-order...
In this problem, y = c1ex + c2e−x  is a two-parameter family of solutions of the second-order DE y'' − y = 0. Find a solution of the second-order IVP consisting of this differential equation and the given initial conditions. y(−1) = 8,    y'(−1) = −8 y=
Given that ? = ?1 ?x + ?2 ?-x is a two-parameter family of solutions of...
Given that ? = ?1 ?x + ?2 ?-x is a two-parameter family of solutions of ?′′ − ? = 0 on the interval (−∞, ∞), find a member of the family satisfying the initial conditions: ?(0) = −1, ?′(0) = 2.
On page 51 we showed that a one-parameter family of solutions of the first-order differential equation...
On page 51 we showed that a one-parameter family of solutions of the first-order differential equation dy/dx=xy^(1/2) is y=((1/4)x^4+c)^2 for c>=0. Each solution in this family is defined on (-inf,inf). The last statement is not true if we choose c to be negative. For c=-1, explain why y=((1/4)x^4+c)^2 is not a solution of the DE on the interval (-inf,inf). Find an interval of definition I on which y=((1/4)x^4+c)^2 is a solution of the DE.
(a) Use the fact that 5x2 − y2 = c is a one-parameter family of solutions...
(a) Use the fact that 5x2 − y2 = c is a one-parameter family of solutions of the differential equation y dy/dx = 5x to find an implicit solution of the initial-value problem y dy/dx = 5x, y(4) = −10. Then sketch the graph of the explicit solution of this problem. Give the interval I of definition of the explicit solution. (Enter your answer using interval notation.) (b) Are there any explicit solutions of y dy/dx = 5x  that pass through...
(a) Verify that all members of the family y = (2)1/2 (c - x2)-1/2 are solutions...
(a) Verify that all members of the family y = (2)1/2 (c - x2)-1/2 are solutions of the differential equation. (b) Find a solution of the initial-value problem. y(x) is what
Verify that all members of the family y = (2)1/2 (c - x2)-1/2 are solutions of...
Verify that all members of the family y = (2)1/2 (c - x2)-1/2 are solutions of the differential equation Find a solution of the initial-value problem. y' = (xy^3)/2 , y(0) = 9
(a) Verify that all members of the family y = (6)1/2 (c - x2)-1/2 are solutions...
(a) Verify that all members of the family y = (6)1/2 (c - x2)-1/2 are solutions of the differential equation. (b) Find a solution of the initial-value problem.
In this problem, x = c1 cos t + c2 sin t is a two-parameter family...
In this problem, x = c1 cos t + c2 sin t is a two-parameter family of solutions of the second-order DE x'' + x = 0. Find a solution of the second-order IVP consisting of this differential equation and the given initial conditions. x(π/6) = 1 2 , x'(π/6) = 0 x=
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT