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solve x2y'' = xy' + (y')3 // note; that's (y')^3 // // // sorry for the...

solve x2y'' = xy' + (y')3 // note; that's (y')^3 // // // sorry for the typo. // it is now written correctly

I think can be solved by using say z = y'... using this we'll get to a Bernoulli to solve...and proceed from them

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