Unimpressed with your previous stunt, the director of the new James Bond movie has come to you with a more exciting idea. In this stunt, Bond will run towards a bridge that is 22m above a river. His partner is in a speedboat 65 meters away from the bridge. Bond jumps horizontally off the bridge with a speed of 6.7 m/s toward where his partner is waiting. Starting from rest, his partner begins racing toward the bridge the moment Bond jumps.
This problem is based on projectile motion and kinematics,
As bond jumps horizontally, there is no vertical component of velocity.
We can find the time in air for Bond.
hf = hi + vyt + 1/2ayt2
0 = 22 + 0 - 1/2 * 9.8 * t2
t = 2.1189 seconds
distance covered by bond, d = vt
d = 6.7 * 2.1189
d = 14.197 m
Therefore, Bond's partner has only 2.1189 seconds and have a distance of 65 - 14.197 = 50.803 m to catch him.
Using kinematics, we have
d = ut + 1/2at2
as his partner starts from rest, u = 0
so,
d = 1/2at2
a = 2d / t2
a = 2 * 50.803 / 2.11892
a = 22.63 m/s2
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