Use two truth tables to show that the pair of compound statements are equivalent.
p ∨ (q ∧ ~p); p ∨ q
p | q | p | ∨ | (q | ∧ | ~p) |
T | T | ? | ? | ? | ? | ? |
T | F | ? | ? | ? | ? | ? |
F | T | ? | ? | ? | ? | ? |
F | F | ? | ? | ? | ? | ? |
p | ∨ | q |
T | ? | T |
T | ? | F |
F | ? | T |
F | ? | F |
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