Question

Solve the following differential equations.

a.) dy/dx+2xy=x, y(0)=2

b.) ?^2(dy/dx)−?y=−y^2

Answer #1

Here are the solutions.

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differential equations solve
(2xy+6x)dx+(x^2+4y^3)dy, y(0)=1

Homogeneous Differential Equations:
dy/dx = xy/x^(2) - y^(2)
dy/dx = x^2 + y^2 / 2xy

exact differential equation, (2xy+x)dx+(x^2+y)dy=0

solve the differential equation
(2y^2+2y+4x^2)dx+(2xy+x)dy=0

Solve the following Differential equations
a) x sin y dx + (x^2 + 1) cos y dy = 0

solve ivp: (y+6x^2)dx + (xlnx-2xy)dy = 0, y(1)=2, x>0

Solve the given differential equations:
a) dy/dx=(x+1)^2
b) (x+1)dy/dx-xy=x^2+x

(x-y)dx + (y+x)dy =0 Solve the differential equation

Use the method for solving homogeneous equations to solve the
following differential equation.
(9x^2-y^2)dx+(xy-x^3y^-1)dy=0
solution is F(x,y)=C, Where C= ?

Solve the system of differential equations using laplace
transformation
dy/dt-x=0,dx/dt+y=1,x(0)=-1,y(0)=1

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