Question

Given (k is a constant): x + y + kz = 1 kx + y +...

Given (k is a constant):

x + y + kz = 1

kx + y + z = 3

2kx + 4y + 4z = 3k +12

Find the values of "k" for which the system has:

1. A unique solution.
2. Infinitely many solutions.
3. No solution.

b. Plug k = −2 and find the solution for the system

c. Plug k = 0 and find the solutions for the system.

d. Find the solution for k = 0 and y = 5.

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