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Consider the function f : [0,1]→R defined by (f(x) =0 if x = 0) and (f(x)=1 if 0 < x≤1)
(i)Compute L(f) andU(f).
(ii) Is f Riemann integrable on [0,1]?
So here U(f)=L(f)=1 and hence f is Riemann integrable and the integral value is 1.
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