Question

Find the solution of ?″+2?′=40sin(2?)+16cos(2?)y″+2y′=40sin⁡(2t)+16cos⁡(2t) with ?(0)=1y(0)=1 and ?′(0)=5.y′(0)=5. y = ?

Find the solution of

?″+2?′=40sin(2?)+16cos(2?)y″+2y′=40sin⁡(2t)+16cos⁡(2t)

with ?(0)=1y(0)=1 and ?′(0)=5.y′(0)=5.

y = ?

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
y''-2y'-3y=15te^2t y(0)=2 y'(0)=0 find the solution
y''-2y'-3y=15te^2t y(0)=2 y'(0)=0 find the solution
Find the solution of the initial value problem y′′+2y′+5y=16e^−tcos(2t), y(0)=6, y′(0)=0
Find the solution of the initial value problem y′′+2y′+5y=16e^−tcos(2t), y(0)=6, y′(0)=0
Use Laplace transform to solve IVP 2y”+2y’+y=2t , y(0)=1 , y’(0)=-1
Use Laplace transform to solve IVP 2y”+2y’+y=2t , y(0)=1 , y’(0)=-1
Find the general solution using Variation of Parameters. y''-y'-2y=2e^(2t)
Find the general solution using Variation of Parameters. y''-y'-2y=2e^(2t)
Use undetermined coefficients to find the particular solution to 1) y''−2y'+3y= 5t^2+2t+2 yp(t)=? 2) y''+y'−20y= −2550sin(3t)...
Use undetermined coefficients to find the particular solution to 1) y''−2y'+3y= 5t^2+2t+2 yp(t)=? 2) y''+y'−20y= −2550sin(3t) yp(t)=?
Find a particular solution to the differential equation −4y″+4y′−1y=−1t^2+2t+2e^3t.
Find a particular solution to the differential equation −4y″+4y′−1y=−1t^2+2t+2e^3t.
Find the general solution of the equation. d^2y/dt^2-2t/(1+t^2)*dy/dt+{2/(1+t^2)}*y=1+t^2
Find the general solution of the equation. d^2y/dt^2-2t/(1+t^2)*dy/dt+{2/(1+t^2)}*y=1+t^2
y"-3y''''+2y= te^2t, y(0)=1, y''(0)=4 solve
y"-3y''''+2y= te^2t, y(0)=1, y''(0)=4 solve
2. Find the solution to the following IVP: 2y'' +2y' -2y = 6x^2 - 4x -1...
2. Find the solution to the following IVP: 2y'' +2y' -2y = 6x^2 - 4x -1 y(0) =-32 y'(0) =5
Find a particular solution to the differential equation −4y″+4y′−1y=−1t^2+2t+2e^3t. yp=
Find a particular solution to the differential equation −4y″+4y′−1y=−1t^2+2t+2e^3t. yp=
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT