A rectangular box is placed in the "octant" x,y,z is less than or equal to 0, with one corner at the origin, the three adjacent faces in the coordinate planes, and the opposite point constrained to lie on the paraboloid: 10x + y2 + z2 = 1
Maximize the volume of the box.
Here, I've taken x, y and z as length, breadth and height of rectangular box, so, x,y,z can not be negative.
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