If m>1 then x^m sin(1/x^n) will be differentiable at 0
Q1. if we take limit x to 0 sin(1/x^n), we get sin(1/0) it doesn't make sense even if m>1
Q2. why when M=1, it will not differentiable at 0?
Q3 Please tell me that limit x to infinity sin(1/x) DNE becasue limit will be -1 and 1???? is that the reason?
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