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Suppose that a die is loaded so that p(1) = .05, p(2) = .25, p(3) =...

Suppose that a die is loaded so that p(1) = .05, p(2) = .25, p(3) = .30, p(4) = .05, p(5) = .10, and p(6) = .25. What is the probability that out of 18 rolls of the die, there are three 1's, two 2's, four 3's, five 4's, one 5, and three 6's? Show your work.

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