Question

solve differential equation by variation of parameters

y''+y=sec(theta) tan(theta)

Answer #1

Here we solve the given differential equation y'' + y = sec(theta)tan(theta)

by using variation of parameter ,so read carefully

solve differential equation by variation of parameters
y''+y=sec(theta) tan(theta)
simple and clear answer no need for writing words just do the
math

solve differential equation by variation of parameters
y''+y=sec(theta) tan(theta)
simple and clear answer no need for writing words just do the
math one page is enough if you could

1) Consider the following differential equation to be solved by
variation of parameters.
y'' + y = sec(θ) tan(θ)
Find the complementary function of the differential
equation.
yc(θ) =
Find the general solution of the differential equation.
y(θ) =
2) Solve the given differential equation by undetermined
coefficients.
y'' + 5y' + 4y = 8
y(x) =

Solve the differential equation by variation of parameters.
5y'' − 10y' + 10y = ex sec(x)
y(x) = ______.

Solve the following differential equation by variation of
parameters. Fully evaluate all integrals.
y′′+9y=sec(3x).
a. Find the most general solution to the associated homogeneous
differential equation. Use c1 and c2 in your
answer to denote arbitrary constants, and enter them as c1 and
c2.
b. Find a particular solution to the nonhomogeneous differential
equation y′′+9y=sec(3x).
c. Find the most general solution to the original nonhomogeneous
differential equation. Use c1 and c2 in your
answer to denote arbitrary constants.

Solve the differential equation by variation of parameters.
y'' + 4y = sin(2x)

Use variation of parameters to solve the following differential
equations
y''+4y'+4y=e^(t)tan^-1(t)

solve the given differential equation by variation of
parameters.
y”+y=1/cos(x)

Solve the differential equation by variation of parameters.
y'' + 3y' + 2y = 1 / (7 + e^x)

differential equations!
find the Differential Equation General Solve by using
variation of parameters method...
y''' - 3y'' +3y' - y =12e^x

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