Question

Solve the first order homogeneous differential equation:

(2x-5y)dx + (4x-y) dy=0

Answer #1

Solve the differential equation (5x^4 y^2+ 2xe^y - 2x cos (x^2)) dx
+ (2x^5y + x^2 e^y) dy = 0.

Homogenous Differential Equations:
dy/dx = y - 4x / x-y
dy/dx = - (4x +3y / 2x+y)

differential equation(2x+3y)dx+ (y+2)dy=0

Solve the Homogeneous differential equation
(7 y^2 + 1 xy)dx - 1 x^2 dy = 0
(a) A one-parameter family of solution of the equation is y(x)
=
(b) The particular solution of the equation subject to the
initial condition y(1) =1/7.

(x-y)dx + (y+x)dy =0 Solve the differential equation

solve the differential equation
(2y^2+2y+4x^2)dx+(2xy+x)dy=0

find the solution of the first order differential equation
(e^x+y + ye^y)dx +(xe^y - 1)dy =0 with initial value y(0)= -1

Use the method for solving homogeneous equations to solve the
following differential equation.
(9x^2-y^2)dx+(xy-x^3y^-1)dy=0
solution is F(x,y)=C, Where C= ?

Solve the following equation using integrating factor.
y dx + (2x − ye^y) dy = 0

Solve the given differential equation
y-x(dy/dx)=3-2x2(dy/dx)

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