Question

Show that the IVP dy/dx = xy^(3/2) y(2) = 0 has a solution but it may...

Show that the IVP

dy/dx = xy^(3/2)

y(2) = 0

has a solution but it may or may not be unique (i.e. the Existence and Uniqueness Theorem doesn’t
imply uniqueness). (Remark: Make sure to draw an appropriate rectangular region.)

Math   Advanced-Math   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
dy/dx = ysin(4x)/(y-4) a) Find region of xy plane where the d.e has a unique solution...
dy/dx = ysin(4x)/(y-4) a) Find region of xy plane where the d.e has a unique solution b) Solve the d.e by seperation of variables. Is there a lost solution? c) Find the solution of the ivp where the initial condition is y(-pi) = -1
Evaluate ∮C(x^3+xy)dx+(cos(y)+x2)dy∮C(x^3+xy)dx+(cos(y)+x^2)dy where C is the positively oriented boundary of the region bounded by  C:0≤x^2+y^2≤16, x≥0,y≥0C:0≤x^2+y^2≤16,x≥0,y≥0
Evaluate ∮C(x^3+xy)dx+(cos(y)+x2)dy∮C(x^3+xy)dx+(cos(y)+x^2)dy where C is the positively oriented boundary of the region bounded by  C:0≤x^2+y^2≤16, x≥0,y≥0C:0≤x^2+y^2≤16,x≥0,y≥0
solve ivp: (y+6x^2)dx + (xlnx-2xy)dy = 0, y(1)=2, x>0
solve ivp: (y+6x^2)dx + (xlnx-2xy)dy = 0, y(1)=2, x>0
Do we know whether or not the following IVP has a unique solution? What theorem tells...
Do we know whether or not the following IVP has a unique solution? What theorem tells us and how dy/dx = xy^(1/3)
(x^2-4)dy/dx+xy-x^3+4x=0. y(3)=7
(x^2-4)dy/dx+xy-x^3+4x=0. y(3)=7
Given the IVP x * sqrt(x+1) * y'''-y'+xy=0 when y(1/2)=y'(1/2)=-1 , and y''(1/2)=1 determine the larest...
Given the IVP x * sqrt(x+1) * y'''-y'+xy=0 when y(1/2)=y'(1/2)=-1 , and y''(1/2)=1 determine the larest interval for which the apporpriate existsence and uniqueness therom gaurentees the exsistence of a unique solution, show all work and fully justify why andhow you got that interval.
Consider the IVP (x^2 - 2x)dy/dx = (x-2)y + x^2, y(1)=-2. Solve the IVP. Give the...
Consider the IVP (x^2 - 2x)dy/dx = (x-2)y + x^2, y(1)=-2. Solve the IVP. Give the largest interval over which the solution is defined.
Find general solution to the equations: 1)y'=x-1-y²+xy² 2)xy²dy=(x³+y³)dx
Find general solution to the equations: 1)y'=x-1-y²+xy² 2)xy²dy=(x³+y³)dx
Use the Existence and Uniqueness Theorem to find the maximum interval for the existing unique solution...
Use the Existence and Uniqueness Theorem to find the maximum interval for the existing unique solution for this IVP: ((x^2)-9)y' + (x + 3)y = cosx and y(0) = 0
Solve the IVP: (14y^13 + 8x^3 +42xy^5)dy + (12x^3+24x^2y+7y^6)dx = 0, y(2)=1
Solve the IVP: (14y^13 + 8x^3 +42xy^5)dy + (12x^3+24x^2y+7y^6)dx = 0, y(2)=1
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT