Question

At a certain hotel, guests have come from the following locations: Use Table 3.

Category	North America	Asia	Other	TOTAL
Proportion	60	30	10	100

Category	North America	Asia	Other
Frequency	238	107	45

a.	Choose the appropriate alternative hypothesis at H0: p1 = 0.60, p2 = 0.30, and p3 = 0.10.
	All population proportions differ from their hypothesized values. At least one of the population proportions differs from its hypothesized value.

b.	Calculate the value of the test statistic at H0: p1 = 0.60, p2 = 0.30, and p3 = 0.10. (Round intermediate calculations to at least 4 decimal places and final answer to 2 decimal places.)

Test statistic

c.	Approximate the p-value.
	p-value < 0.005 p-value > 0.100 0.010 < p-value < 0.025 0.025 < p-value < 0.050 0.050 < p-value < 0.100

d.	At 5% significance level, can we reject H0: p1 = 0.60, p2 = 0.30, and p3 = 0.10?
	Yes since the p-value is less than α. Yes since the p-value is more than α. No since the p-value is less than α. No since the p-value is more than α.

rev: 11_05_2015_QC_CS-31836

Question 4 of 6 Total 4 of 6

TIMED HW NEED ANSWER IN 20

Answer 1

(a)

Correct option:

At least one of the population proportions differs from its hypothesized value.

(b)

Test statistic is got as follows:

Category	Observed (O)	Expected (E)	(O - E)2/E
North America	238	390X0.60=234	0.0684
Asia	107	390X0.30=117	0.8547
Other	45	390X0.10=39	0.9231
Total = =			1.8462

So,

Answer is:

Test statistic

1.85

(c)

ndf = 3 - 1 = 2

By Technology, P - Value = 0.3973

So,

Correct option:

Approximate P - value

P - Value > 0.100

(d)
Correct option:

No. since p - value is more than