Answer:)
We see that the truth table for the first statement is
given by::
p | q | ![]() |
0 | 0 | 1 |
0 | 1 | 0 |
1 |
0 |
1 |
1 | 1 | 1 |
Similarly we see that the table for
is :
p | ![]() |
q | ![]() |
![]() |
0 | 1 | 0 | 1 | 1 |
0 | 1 | 1 | 0 | 0 |
1 | 0 | 0 | 1 | 1 |
1 | 0 | 1 | 0 | 1 |
Hence, we see that the truth tables are the same, and hence the two logic statements are equivalent.
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