Question

solve differential equation

(x^2)y'' - xy' +y =2x

Answer #1

solve differential equation ((x)2 - xy +(y)2)dx - xydy
= 0
solve differential equation (x^2-xy+y^2)dx - xydy =
0

differential equation one solution is given,
xy''-(2x+1)y'+(x+1)y=x^2; y_1=e^x

Solve the differential equation (5x^4 y^2+ 2xe^y - 2x cos (x^2)) dx
+ (2x^5y + x^2 e^y) dy = 0.

Solve the differential equation by using integrating factors.
xy' = 4y − 6x^2
y(x)=?

Use undetermined coefficients to solve the differential
equation
y'' + y = x sin 2x

Solve (3D^2+D-14)y=8e^2x +Cos 5x.
Solve the differential equation by variation of
parameter
Solve the differential equation by variation of
parameter (3D^2+D-14)y=8e^2x+Cos 5x

solve the differential equation
xy'+y=4x3y2lnx

Solve the differential equation.
xy + y' = 76x

Solve the following differential equation using taylor series
centered at x=0:
(2+x^2)y''-xy'+4y = 0

Solve the Homogeneous differential equation
(7 y^2 + 1 xy)dx - 1 x^2 dy = 0
(a) A one-parameter family of solution of the equation is y(x)
=
(b) The particular solution of the equation subject to the
initial condition y(1) =1/7.

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