Question

find a general solution using the method of undetermined coefficients for a given differential equation.

y'=[-3 1; 1 -3]y+[-6 2]e^-2t

Please explain it as easily as possible.

Please write so that I can read your handwriting.

Answer #1

Use the method of undetermined coefficients to find a general
solution to the given differential equation:
y''-y'-2y=4te3t+4sin2t

Use the undetermined coefficients method to find the particular
solution of the differential equation y'' + 3y' - 4y =
xe2x and then write the general solution.

Differential Equations
Using the method of undetermined coefficients find the Yp
(particular solution) of the differential equation: y’’ - y = 1 +
e^x

Find the general solution of the equation using the method of
undetermined coefficients: y''-y'=5sin(2x)

Find a particular solution to the differential equation using
the Method of Undetermined Coefficients. 6y''+4y'-y=9

Find a particular solution to the differential equation using
the Method of Undetermined Coefficients.
y''-4y'+8y=xe^x

Find a solution to y"-4y'-5y=2e^2t using the method of
undetermined coefficients
no handwriting unless it is readable

Find a solution to y^''-4y^'-5y=2e^2t using variation of
parameters. Find the solution to the differential equation in
problem 6, this time using the method of undetermined
coefficients.

find the solution of these nonhomogeneous differential equations
by using the method of undetermined coefficients
y"- y' - 6y = 18x^(2) + 5

Solve the differential equation using method of Undetermined
Coefficients. y'' + y = t^3, y(0) = 1, y'(0) = -1

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