Show how a contradiction arises from the following taken as an assumption
(∃y)(x)(x∈y≡∼(x∈x))
The assumption tells us that
The statement that there exists such that forall , belongs to is equivalent to the statement is not contained in .
The contradiction arises because the statement " is not contained in " is not true even if the statement "there exists such that forall " is true.
Consider the set of rationals .
Obviously there exists the set of reals such that i.e. is contained in but is also contained in i.e. also holds.
Hence the assumption is wrong.
Get Answers For Free
Most questions answered within 1 hours.