Question

*Biosystems Engineering - Food Science

1. Vegetable oil at 25℃ (density = 910 kgm3, viscosity 0.084 Pa s) s flowing with a volumetric average velocity of 0.85 m/s through 2 inch smooth (Ɛ = 0) steel tubing (ID = 4.749 cm)

   1. What is the Reynolds number for this flow situation?

   2. What is the friction factor?

   3. What is the pressure drop over the 120 m section of pipe?

Answer 1

The Reynolds Number is found from the equation,

Reynolds Number, R: 467

Plate flow is still laminar at a distance D from the leading edge.

Pipe flow is laminar in a pipe of diameter D.

b)

The friction factor for laminar flow is calculated by dividing 64 by the Reynold's number.

Friction factor (for laminar flow) = 64 / Re

so the friction factor is 0.136810603

c)