Question

4.) NSTRUCTIONS: Select the conclusion that follows in a single step from the given premises. Given...

4.)

NSTRUCTIONS: Select the conclusion that follows in a single step from the given premises.

Given the following premises:

1. ∼M ⊃ S
2. ∼M
3. (M ∨ H) ∨ ∼S
a.

M ∨ H                          3, Simp

b.

M ∨ (H ∨ ∼S)              3, Assoc

c.

∼S                               1, 2, MP

d.

∼ M ∨ S                          1, Impl

e.

H                                  2, 3, DS

3.)

NSTRUCTIONS: Select the conclusion that follows in a single step from the given premises.

Given the following premises:

1. G • ∼A
2. K ⊃ (G • ∼A)
3. G ⊃ M
a.

M                           1, 3, MP

b.

K ⊃ (∼A • G)         2, Com

c.

(K ⊃ G) • ∼A         2, Assoc

d.

(K ⊃ G ) ⊃ ∼A      2, Exp

e.

K                           1, 2, MP

2.)

INSTRUCTIONS: Select the conclusion that follows in a single step from the given premises.

Given the following premises:

1. ~~A
2. G ⊃ (A ⊃ ∼L)
3.

∼A ∨ ∼G

a.

G                              1, 3, DS

b.

(G ⊃ A) ⊃ ∼L             2, Assoc

c.

∼L                               1, 2, MP

d.

A ∨ G                          3, DN

e.

G ⊃ (∼∼L ⊃ ~A)          2, Trans

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
In the space provided, derive the conclusion shown from the premises given. HINT: Don't forget about...
In the space provided, derive the conclusion shown from the premises given. HINT: Don't forget about the derived rules, substitution rules and subderivation rules. 1. A ⊃ C 2. ~(D v A) ⊃ B   ∴  ~(C v B)  ⊃ (D • ~A) ————————————————————————— 1. A ⊃ ~(C v D)                                                                 2. ~A v D             ∴  ~A                                                                  
Draw the Activity-on-Arrow (AoA) and Activity-on-Node (AoN) networks using the activity dependency table given below and...
Draw the Activity-on-Arrow (AoA) and Activity-on-Node (AoN) networks using the activity dependency table given below and find the critical path(s) Activities Predecessor duration A - 2 B - 10 C A 9 D A,B 7 E A,B 9 F B 5 G C 10 H D,E 1 I D,E,F 2 J F 7 K C,H,I 2 L I,J 2 M I 1 N G,K 5
Part IV: All of the following arguments are VALID. Prove the validity of each using NATURAL...
Part IV: All of the following arguments are VALID. Prove the validity of each using NATURAL DEDUCTION. 1) 1. H É I 2. U v ~I 3. ~U 4. H v S                                               / S 2) 1. (I × E) É (F É Y) 2. Y É ~C 3. I × E                                                 / F É ~C 3) 1. L v O 2. (F v C) É B 3. L É F 4. O É C                                              / B 4) 1. K ×...
QUESTION 2. The following table explain the logical relationship of activities of a given project, including...
QUESTION 2. The following table explain the logical relationship of activities of a given project, including the duration in weeks of each activity. Activity Follows Duration (Weeks) M G, F 4 F Start 6 G Start 3 D Start 7 K D, G 5 L K, J 8 J D 3 S L, M, F 4 Finish S Draw the network Perform the forward path as determine the project duration (5 Marks) Perform the back path and determine the critical...
Which of the following signals is the impulse response of a relaxed system having a unit...
Which of the following signals is the impulse response of a relaxed system having a unit step response of: s(t) = 3 t exp( -2 t) u(t) - 3 exp( -2 t) u(t) + 0.5 u(t) Select one: a. h(t) = 9 t exp( -2 t) u(t) - 6 exp( -2 t) u(t) + 0.5 d(t) b. h(t) = -6 t exp( -2 t) d(t) + 9 exp( -2 t) d(t) c. h(t) = 3 t exp( -2 t) d(t)...
Using the following code: % Ex 6.4 First-order step and impulse response for two time constants...
Using the following code: % Ex 6.4 First-order step and impulse response for two time constants % clear all; close all; t = 0:.1:100; % Time vector subplot(1,2,1); x = 250*exp(-0.05*t); plot(t,x,'k'); xlabel('Time (hrs)','FontSize',14); ylabel('P_A (mmHg)','FontSize',14); title('Impulse Response','FontSize',14); subplot(1,2,2); x = 20*(1-exp(-0.05*t)); plot(t,x,'k'); xlabel('Time (hrs)','FontSize',14); ylabel('P_A (mmHg)','FontSize',14); title('Step Response','FontSize',14);    ANSWER: The response of a 1st order linear body fluid balance system to step function (L m (t) = 1/s, Eqn. 6.9/p226) and impulse function (L d (t) = 1,...
Match the statement to the correct answer. (Some reagents can be used more than once.) The...
Match the statement to the correct answer. (Some reagents can be used more than once.) The flowchart along with the report sheets in experiment 5 should be very helpful. A 6M Nitric Acid (HNO3) B Colbalt Nitrate (Co(NO3)2) C Disodium EDTA (Na2EDTA) D Aluminum Nitrate (Al(NO3)3) E Zinc Nitrate (Zn(NO3)2 F Barium Nitrate (Ba(NO3)2) G 6M Hydrochloric Acid (HCl) H OH-, CO32-, and PO43- I Lead chloride (PbCl2(s)) J 0.1M sodium carbonate (Na2CO3) K NH4+(aq) and OH-(aq) L Silver chloride...
Activities Predecessors Duration(weeks) Labour A 4 5 B A 3 5 C B 2 5 D...
Activities Predecessors Duration(weeks) Labour A 4 5 B A 3 5 C B 2 5 D C 1 5 E B 2 5 F E 8 5 G D 10 5 H B 2 5 I B 3 5 J F,G,I 3 5 K H 2 5 L J,K 3 5 M L 1 5 i.Construct an activity on the arrow network ii. Determine the Duration of the Critical Path; iii. Draw the corresponding Gantt chart iv. Draw the resource...
The electron concentration gradient of some material is dn/dx=1017cm-4, and the Constant Table: e0 =8.85´10-12C2×N--1×m-2 ;...
The electron concentration gradient of some material is dn/dx=1017cm-4, and the Constant Table: e0 =8.85´10-12C2×N--1×m-2 ; R=8.315J-mol-1×K-1; m0= 4π´10-7N×A-2; h = 6.63´10-34J×s; e = 1.602´10-19C; G=6.67´10-11N×m2-kg-2; me=9.11´10-31kg; g=9.8 m/s2; mobility of the electron is 1350 cm2/V.s,calculate: (a) the diffusion coefficient of the electron, assuming kT=0.0259ev at T = 300 K. (b) the diffusion current density of electrons.
I nee to make two graphs . 1) Title Fe (s) [ Fe +2 (aq 1M)...
I nee to make two graphs . 1) Title Fe (s) [ Fe +2 (aq 1M) // Cu 2+ ( aq , 1 M) / Cu (s). The data used for the graph is as follows: x-axis = Temp in Kelvin, y-axis = E ( vol) Pt 1) At 5 C (278 K) E = 0.62 V Pt 2) At 50 C ( 323 K) E = 0. 75 V Pt 3) At 75 C( 348 K) E = 0.84V...