Note That: . where pi's are distinct primes
Then number of positive divisor of n =
a)
Total number of positive divisor = (6+1)(5+1)(6+1)
=7×6×7 =
b) number of positive divisor of both given number = number of positive divisor of their g.c.d
Now, g.c.d.(243000000,1440000)=
Now,
Number of positive divisor, = (6+1)(2+1)(4+1)=7×3×5=
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