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Let X,Y be posets. Define a relation ≤ on X × Y by the reciepe:                ...

Let X,Y be posets. Define a relation ≤ on X × Y by the reciepe:

                (x1,y1) ≤(x2,y2) iff   x1 ≤ x2     in X   and y1 ≤ y2 in Y

In Above example check that (X ×Y,≤) is actually a poset, It is the product poset of X and Y

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