Question

Use the Laplace transform to solve the following initial value
problem

y”+4y=cos(8t)

y(0)=0, y’(0)=0

First, use Y for the Laplace transform of y(t) find the
equation you get by taking the Laplace transform of the
differential equation and solving for Y:

Y(s)=?

Find the partial fraction decomposition of Y(t) and its
inverse Laplace transform to find the solution of the IVP:

y(t)=?

Answer #1

Use the Laplace transform to solve the following initial value
problem:
y′′ + 8y ′+ 16y = 0
y(0) = −3 , y′(0) = −3
First, using Y for the Laplace transform of y(t)y, i.e., Y=L{y(t)},
find the equation you get by taking the Laplace transform of the
differential equation
__________________________ = 0
Now solve for Y(s) = ______________________________ and write the
above answer in its partial fraction decomposition, Y(s) = A /
(s+a) + B / ((s+a)^2)
Y(s) =...

Consider the
differential equation
y′′(t)+4y′(t)+5y(t)=74exp(−8t),
with initial conditions y(0)=12, and
y′(0)=−44.
A)Find the Laplace
transform of the solution Y(s).Y(s). Write the
solution as a single fraction in s.
Y(s)=
______________
B) Find the partial
fraction decomposition of Y(s). Enter all factors as first order
terms in s, that is, all terms should be of the form
(c/(s-p)), where c is a constant and the root p is a constant. Both
c and p may be complex.
Y(s)= ____ + ______...

Solve the initial value problem using the method of
the laplace transform.
y"+4y'+4y=8t,y(0)=-4,y'(0)=4

Consider the initial value problem
y′′+4y=16t,y(0)=8,y′(0)=6.y″+4y=16t,y(0)=8,y′(0)=6.
Take the Laplace transform of both sides of the given
differential equation to create the corresponding algebraic
equation. Denote the Laplace transform of y(t) by Y(s). Do not move
any terms from one side of the equation to the other (until you get
to part (b) below).
Solve your equation for Y(s)
Y(s)=L{y(t)}=__________
Take the inverse Laplace transform of both sides of the
previous equation to solve for y(t)y(t).
y(t)=__________

use the Laplace transform to solve the initial value
problem.
y''+4y=4, y(0)=0, y'(0)=1
please provide details on how to apply partial
fractions

Use the Laplace transform to solve the following initial value
problem:
y′′−4y′−32y=δ(t−6)y(0)=0,y′(0)=0

Consider the following initial value problem: y′′+49y={2t,0≤t≤7
14, t>7 y(0)=0,y′(0)=0 Using Y for the Laplace transform of
y(t), i.e., Y=L{y(t)}, find the equation you get by taking the
Laplace transform of the differential equation and solve for
Y(s)=

use the laplace transform to solve the initial value problem:
y"+4y=4t, y(0)=1, y'(0)=0

use the laplace transform to solve initial value
problem
y"+4y'+20y=delta(t-2)
y(0)=0, y'(0)=0
use step t-c for uc(t)

Use the Laplace transform to solve the IVP:
y′(t) +y(t) = cos(t),
y(0) = 0.

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